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@ -207,25 +207,32 @@ public:
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/*
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this method produces: year.month.day, eg. 1990.02.12
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this method outputs to the given stream: YYYY-MM-DD, eg. 1990.02.12
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ISO 8601 format
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*/
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template<class Stream>
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void SerializeDay(Stream & out) const;
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/*
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this method produces: hour:min:sec, eg: 13:05:39
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this method outputs to the given stream: HH:MM:SS, eg: 13:05:39
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ISO 8601 format
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*/
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template<class Stream>
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void SerializeHour(Stream & out) const;
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/*
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this method produces: year.month.day our:min:sec, eg: 1990.02.12 13:05:39
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this method outputs to the given stream: YYYY-MM-DD HH:MM:SS, eg: 1990-02-12 13:05:39
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ISO 8601 format
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*/
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template<class Stream>
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void Serialize(Stream & out) const;
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/*
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the date
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*/
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int year; // 1970 - ...
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int month; // 1 - 12
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int day; // 1 - 31
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@ -259,9 +266,10 @@ void Date::SerializeInt(Stream & out, int val) const
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template<class Stream>
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void Date::SerializeDay(Stream & out) const
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{
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out << year << '.';
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// !! IMPROVE ME the year should be printed with 4 digits, e.g. 0001 when the year is equal to one
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out << year << '-';
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SerializeInt(out, month);
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out << '.';
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out << '-';
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SerializeInt(out, day);
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}
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